std::has_virtual_destructor
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                    | Defined in header  <type_traits> | ||
| template< class T > struct has_virtual_destructor; | (since C++11) | |
If T is a type with a virtual destructor, provides the member constant value equal true. For any other type, value is false.
If T is a non-union class type, T shall be a complete type; otherwise, the behavior is undefined.
| Contents | 
[edit] Helper variable template
| template< class T > inline constexpr bool has_virtual_destructor_v = has_virtual_destructor<T>::value; | (since C++17) | |
Inherited from std::integral_constant
Member constants
| value [static] | true if Thas a virtual destructor , false otherwise(public static member constant) | 
Member functions
| operator bool | converts the object to bool, returns value(public member function) | 
| operator() (C++14) | returns value(public member function) | 
Member types
| Type | Definition | 
| value_type | bool | 
| type | std::integral_constant<bool, value> | 
[edit] Notes
If a class has a public virtual destructor, it can be derived from, and the derived object can be safely deleted through a pointer to the base object (GotW #18)
[edit] Example
Run this code
#include <iostream> #include <type_traits> #include <string> #include <stdexcept> int main() { std::cout << std::boolalpha << "std::string has a virtual destructor? " << std::has_virtual_destructor<std::string>::value << '\n' << "std::runtime_error has a virtual destructor? " << std::has_virtual_destructor<std::runtime_error>::value << '\n'; }
Output:
std::string has a virtual destructor? false std::runtime_error has a virtual destructor? true
[edit] See also
| (C++11)(C++11)(C++11) | checks if a type has a non-deleted destructor (class template) | 


